39 Come on! let us solve!-1

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   Let us solve our problems!

A car runs at a constant speed of 30 km /p/h;

A bike runs at the regular increasing speed by 1 km for the

succeeding hours,commencing from 1km/p/h;

Both they start a race from one place at the same time;

Will they meet again?

If so,when and where will they meet?

Solve:

Let the meeting hour be X;

So the final speed of the bike is also X;

Accordingly,

The distance run by the car=The distance run by the bike.

The distance run by the car=Xx30

The distance run by the bike=Xx(X/2+1/2)

Therefore,Xx30=Xx(X/2+1/2);Strike out X,both sides;

=30=X/2+1/2;  =30x2=X+1;  =60=X+1;  X+1=60;  X=60--1=59.

X is the meeting hour of the vehicles.

So,both they will meet at 59th hour.

And on the 59th hour the speed of the bike is 59 km/p/h

The distance:  The car=59x30=1770 km; 

The bike=59x(59/2+1/2)=59x60/2=59x30=1770 km

Both they will meet at 1770 km,distance.